Comment factoriser: J=4x²-9+(2x+3)(x-1)
Mathématiques
LeGalerienDesMaths
Question
Comment factoriser:
J=4x²-9+(2x+3)(x-1)
J=4x²-9+(2x+3)(x-1)
1 Réponse
-
1. Réponse néèzhàà
J=4x²-9+(2x+3)(x-1)
= (2x)² - 3² +(2x+3)(x-1)
= (2x-3)(2x+3)+(2x+3)(x-1)
= (2x+3)[(2x-3)+(x-1)]
= (2x+3)(2x-3+x-1)
= (2x+3)(3x-4)