Mathématiques

Question

Aider moi develloper et reduire
Il y aura les lettre x et y

C = -(5-x)(2x+3)-(2x+1)(3x+6)

et l'autre

D = (2y+2)(5y-2)-(5y+1)(2y-1)

1 Réponse

  • C = -(5-x)(2x+3)-(2x+1)(3x+6)
    c= -(10x+15-2x²-3x) -(6x²+12x+3x+6)
    c = +2x²-7x-15 -6x²-15x-6
    c =-4x²-22x-21


     D = (2y+2)(5y-2)-(5y+1)(2y-1)
    d = 10y²-4y+10y-4 -(10y²-5y+2y-1)
    d = 10y²+6y-4-10y²+3y+1
    d = 9y-3

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