Pouvez vous m'aider à résoudre cette équation? (3x+2)²=9x+6 Merci

(3x+2)² = 9x+6

(3x+2)²-9x+6 = 0

(3x+2)²-3(3x+2) = 0

(3x+2)(3x+2-3) = 0

(3x+2)(3x-1) = 0

3x+2 = 0
3x = -2
x =-2/3

3x-1 = 0
3x = 1
x = 1/3

(3x+2)² =9x+6
(3x+2)² -(9x+6) =0
(3x+2)² -3(3x+2) =0
(3x+2)(3x+2-3) =0
(3x+2)(3x-1) =0

3x+2 =0                               3x-1 =0
3x = -2                                  3x = 1
x = -2/3                                    x =1/3