Developper: A=(4x+3)(5x+7); B=(5x+1)(4+3x); C=(5x-1)(1+3x)
Mathématiques
Meelani
Question
Developper:
A=(4x+3)(5x+7);
B=(5x+1)(4+3x);
C=(5x-1)(1+3x)
A=(4x+3)(5x+7);
B=(5x+1)(4+3x);
C=(5x-1)(1+3x)
2 Réponse
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1. Réponse maudmarine
A=(4x+3)(5x+7)
A = 20x² + 28x + 15x + 21
A = 20x² + 43x + 21
B=(5x+1)(4+3x)
B = 20x + 15x² + 4 + 3x
B = 15x² + 20x + 3x + 4
B = 15x² + 23x + 4
C=(5x-1)(1+3x)
C = 5x + 15x² - 1 - 3x
C = 15x² + 5x - 3x - 1
C = 15x² + 2x - 1 -
2. Réponse MrEagle
A = ( 4x + 3 ) ( 5x + 7 )
= 4x * 5x + 4x * 7 + 3 * 5x + 3 * 7
= 20x² + 28x + 15x + 21
= 20x² + 43x + 21
B = (5x + 1 ) ( 4 + 3x )
= 5x * 4 + 5x * 3x + 1 * 4 + 1 * 3x
= 20x + 15x² + 4 + 3x
= 15x² + 23x + 4
C = ( 5x - 1 ) ( 1 + 3x )
= 5x * 1 + 5x * 3x - 1 * 1 - 1 * 3x
= 5x + 15x² - 1 - 3x
= 15x² + 2x - 1