حل المعادلات التالية (x-1)(x+3)=0 -2x+4=0 -8x-6=0 3x+(1-2x)=4x-(x-2)

x-1=0 ou x+3=0
x=1 ou x=-3
-2x+4=0 ⇔-2x=-4⇔x=2
-8x-6=0 ⇔-8x=6⇔x=-6/8=3/4
3x+(1-2x)=4x-(x-2)⇔3x+1-2x=4x-x+2⇔3x-2x+x-4x=2-1⇔-2x=1⇔x=-1/2