4x²-1 =2x-1 (5x+12) (5-2x)+(5x+12)(3x-3) = 0 4x²+12x+9=0 x²-36=0 x²-2x=-1
Mathématiques
loubet07
Question
4x²-1 =2x-1
(5x+12) (5-2x)+(5x+12)(3x-3) = 0
4x²+12x+9=0
x²-36=0
x²-2x=-1
(5x+12) (5-2x)+(5x+12)(3x-3) = 0
4x²+12x+9=0
x²-36=0
x²-2x=-1
1 Réponse
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1. Réponse choune88
4x² - 1 = 2x - 1
4x² - 2x = 0
x = 0
(5x+12)(5-2x) + (5x+12)(3x-3) = 0
(5x+12)(5-2x+3x-3) = 0
(5x+12)(x+2) = 0
5x+12 = 0
5x = - 12
x = -12/5
x+2 = 0
x = -2
(5x+12)(5-2x) + (5x+12)(3x-3) = 0 pour x= -2 ou x = -12/5
4x²+12x+9=0
(2x+3)² = 0
2x + 3 = 0
2x = -3
x = -3/2
4x²+12x+9=0 pour x = -3/2
x²-36 = 0
(x - 6)(x+6) = 0
x - 6 = 0
x = 6
x + 6 = 0
x = -6
x²-36 = 0 pour x = 6 ou x = -6
x² - 2x = -1
x² - 2x + 1 = 0
(x - 1)² = 0
x - 1 = 0
x = 1
x² - 2x = -1 pour x = 1