resoudre les equations suivantes: 2x+4(x-2)=3(2x-2) 3-(x+2)²=-x²-2(2x+1)+1 (x-1)(x-pi)=0 (3x+6)²=0 x²-9=0 x²+2x+1=0

2 x + 4 x - 8 = 6 x - 6
6 x - 6 x = - 6 + 8
0 x = 2
x = 0

3 - ( x + 2)² = - x² - 4 x - 2 + 1
3 - x² + 4 x + 4 = - x² - 4 x - 1
- x² + x² + 4 x + 4 x = - 1 - 3 - 4
8 x = - 8
x = - 1

( x - 1) ( x - pi) = 0
soit x - 1 = 0 et x = 1
soit x - pi = 0 et x = pi

x² -9 = 0
(x +3)(x -3) = 0
soit x - 3 = 0 et x = 3
soit x  +3 = 0 et x = - 3

x²+ 2 x +1  = 0
(x + 1)² = 0
(x +1) ( x + 1) = 0
x +1 = 0 et x = -1