Mathématiques

Question

pouvez vous m'aider a résoudre ces équations
a) (2x-4)(9-3x)=0
b) (3x+1)(1+3x)=0
c) 7x(1-2x)=0
d) (5x-10)(8-4x)=0

2 Réponse

  • Bonjour.

    Ce sont toutes des equations-produit nul.

    a) (2x - 4)(9 - 3x) = 0
    2(x - 2) * 3(3 - x) = 0
    6(x - 2)(3 - x) = 0
    (x - 2)(3 - x) = 0
    2 solutions :
    x - 2 = 0 ⇔ x = 2
    3 - x = 0 ⇔ x = 3
    Donc S = {2 ; 3}.

    b) (3x + 1)(1 + 3x) = 0
    (3x + 1)(3x + 1) = 0
    (3x + 1)² = 0
    1 solution :
    3x + 1 = 0 ⇔ 3x = - 1 ⇔ x = -1/3
    Donc S = {-1/3}.

    c) 7x(1 - 2x) = 0
    2 solutions :
    7x = 0 ⇔ x = 0
    1 - 2x = 0 ⇔ 2x = 1 ⇔ x = 1/2
    Donc S = {0 ; 1/2}.

    d) (5x - 10)(8 - 4x) = 0

    5(x - 2) * 4(2 - x) = 0
    20(x - 2)(2 - x) = 0
    (x - 2)(2 - x) = 0
    (x - 2) * (- 1)(x - 2) = 0
    - (x - 2)² = 0
    (x - 2)² = 0
    1 solution :
    x - 2 = 0 ⇔ x = 2
    Donc S = {2}.

    Bon week-end !

  • a)
    (2x - 4) (9 - 3x) = 0
    Il faut factoriser :
    2 (x - 2) * 3 (3 - x) = 0
    6 (x - 3) (3 - x) = 0
    (x - 2) (3 - x) = 0
    x - 2 = 0    ou      x - 3 = 0
    x = 2                  x = 3

    b)
    (3x + 1) (1 + 3x) = 0
    (3x + 1)² = 0
    3x + 1 = 0
    3x = - 1
    x = - 1/3

    c)
    7x (1 - 2x) = 0
    7x = 0      ou    - 2x + 1 = 0
    x = 0                - 2x = - 1
                            x = 1/2

    d)
    (5x - 10) (8 - 4x) = 0

    5(x - 2) * 4(2 - x) = 0
    20(x - 2) (2 - x) = 0
    (x - 2) (2 - x) = 0
    (x - 2)² = 0
    x - 2 = 0
    x = 2

Autres questions