Mathématiques

Question

le 40 et 41 s'il vous plait
le 40 et 41 s'il vous plait

1 Réponse

  • 40/
    a)
    x²+5-54 =0
    x²-49 =0
    (x-7)(x+7) =0

    x-7 =0                 x+7 =0
    x = 7                    x = -7

    b)
    t² -7 = 74
    t²-7-74 =0
    t²-81 =0
    (t-9)(t+9) =0

    t-9 =0                       t+9 =0
    t = 9                          t = -9

    je te laisse faire la c

    41/

    2x² = 18
    2x²-18 =0
    2(x²-9) =0
    2(x-3)(x+3) =0

    x-3 =0                          x+3 =0
    x =3                             x = -3

    b)

    1/3y² = 27
    1/3y²-27 =0
    3(1/9y²-9) =0
    3(1/3y-3)(1/3y+3) =0

    1/3y -3 =0                                   1/3y +3 =0
    1/3y =3                                         1/3y = -3
    y = 3x3                                              y = -3x3
    y = 9                                                 y = -9

    je te laisse faire la derniere meme raisonnement